I am using below code snippet to validate my input string with: only capital letters, numbers and two special characters (those are & and Ñ) & without any space between.

var validpattern = new RegExp('[^A-Z0-9\d&Ñ]');
if (enteredID.match(validpattern))
   isvalidChars = true;
else
   isvalidChars = false;

Test 1: "XAXX0101%&&$#" should fail i.e isvalidChars = false; (as it contains invalid characters like %$#.

Test 2: "XAXX0101&Ñ3Ñ&" should pass.

Test 3: "XA 87B" should fail as it contains space in between

The above code is not working, Can any one help me rectifying the above regex.

I am using below code snippet to validate my input string with: only capital letters, numbers and two special characters (those are & and Ñ) & without any space between.

var validpattern = new RegExp('[^A-Z0-9\d&Ñ]');
if (enteredID.match(validpattern))
   isvalidChars = true;
else
   isvalidChars = false;

Test 1: "XAXX0101%&&$#" should fail i.e isvalidChars = false; (as it contains invalid characters like %$#.

Test 2: "XAXX0101&Ñ3Ñ&" should pass.

Test 3: "XA 87B" should fail as it contains space in between

The above code is not working, Can any one help me rectifying the above regex.

• javascript
• regex
• string

• 3 What about your previous question? – Gumbo Commented Oct 20, 2010 at 11:31
• 1 Maybe you should remove the negation ^. – Ikaso Commented Oct 20, 2010 at 11:33

4 Answers 4

This is happening because you have a negation(^) inside the character class.

What you want is: ^[A-Z0-9&Ñ]+$ or ^[A-Z\d&Ñ]+$

Changes made:

• [0-9] is same as \d. So use either of them, not both, although it's not incorrect to use both, it's redundant.
• Added start anchor (^) and end anchor($) to match the entire string not part of it.
• Added a quantifier +, as the character class matches a single character.

^[A-Z\d&Ñ]+$

0-9 not required.

if you want valid patterns, then you should remove the ^ in the character range.

[A-Z0-9\d&Ñ]

Using jquery we could achieve the same in one line:

$('#txtId').alphanumeric({ allow: " &Ñ" });

Using regex (as pointed by codaddict) we can achieve the same by

var validpattern = new RegExp('^[A-Z0-9&Ñ]+$');

Thanks everyone for the precious response added.