分别用c++,python,java写一个行列转换的算法

分别用c++,python,java写一个行列转换的算法，将这个矩阵转换一下：[[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12]]

以下是使用C++、Python 和 Java 编写的矩阵行列转换算法，并将给定矩阵转置的示例：

C++ 示例：

#include <iostream>
#include <vector>int main() {std::vector<std::vector<int>> matrix = {{1, 2, 3},{4, 5, 6},{7, 8, 9},{10, 11, 12}};int rows = matrix.size();int cols = matrix[0].size();// 创建一个新的矩阵来存储转置结果std::vector<std::vector<int>> transpose(cols, std::vector<int>(rows));// 转置矩阵for (int i = 0; i < rows; i++) {for (int j = 0; j < cols; j++) {transpose[j][i] = matrix[i][j];}}// 打印转置矩阵for (int i = 0; i < cols; i++) {for (int j = 0; j < rows; j++) {std::cout << transpose[i][j] << " ";}std::cout << std::endl;}return 0;
}

Python 示例：

matrix = [[1, 2, 3],[4, 5, 6],[7, 8, 9],[10, 11, 12]
]# 获取原矩阵的行数和列数
rows = len(matrix)
cols = len(matrix[0])# 创建一个新矩阵来存储转置结果
transpose = [[0] * rows for _ in range(cols)]# 转置矩阵
for i in range(rows):for j in range(cols):transpose[j][i] = matrix[i][j]# 打印转置矩阵
for i in range(cols):for j in range(rows):print(transpose[i][j], end=" ")print()

Java 示例：

public class MatrixTranspose {public static void main(String[] args) {int[][] matrix = {{1, 2, 3},{4, 5, 6},{7, 8, 9},{10, 11, 12}};int rows = matrix.length;int cols = matrix[0].length;// 创建一个新的矩阵来存储转置结果int[][] transpose = new int[cols][rows];// 转置矩阵for (int i = 0; i < rows; i++) {for (int j = 0; j < cols; j++) {transpose[j][i] = matrix[i][j];}}// 打印转置矩阵for (int i = 0; i < cols; i++) {for (int j = 0; j < rows; j++) {System.out.print(transpose[i][j] + " ");}System.out.println();}}
}

这些示例会将给定的矩阵转置，并打印出转置后的结果。